 | 1801 - 446 str.
.... 2. Divide The rule which is most commonly made use of is this : RULE. Multiply the last remainder by the preceding divisor, or last but one, and to...and to the product add the next preceding remainder ; nnd so on, till you have, gone through all the divisors and remainders to the first. EXAMPLE. 9)64865... | |
 | Nicolas Pike - 1809 - 312 str.
...divifor is a compoQte number, is, RULE II. Multiply the laft remainder by the preceding, divifor, or lad but one, and to the product add the preceding remainder ; multiply this fum by the next preceding divifor, and to the proclu>£t add the next preceding remainder ; and fo... | |
 | Charles Hutton - 1811 - 406 str.
...as if the division had been performed all at once, proceed as follows ; Multiply the last remainder by the preceding divisor, or last but one, and to...remainders to the first. As in the example following : EXAMPLES. 1. Divide 31046835 by 56 or 7 times 8. 7 ) 31046835 6 the last rem. • mult, 7 preced»... | |
 | Charles Hutton - 1822 - 616 str.
...as if the division had been performed all at once, proceed as follows : Multiply the last remainder by the preceding divisor, or last but one, and to...next preceding divisor, and to the product add the neit preceding remainder ; and so on, till you have gone backward through all the divisors and remainders... | |
 | William Kinne - 1829 - 246 str.
...remainder may be found by the following rule. RULE.— Multiply the last remainder by the last divisor but one, and to the product add the preceding remainder...multiply this sum by the next preceding divisor, and to this product add the next preceding remainder, and so on until all the remainders and divisors are... | |
 | Introduction - 1830 - 102 str.
...Remainder, which will give the true one.When there are more than two Divisors, multiply the last Remainder by the preceding Divisor, or last but one, and to the Product add the preceding Remainder: then multiply this sum by the next preced ing Divisor, and to that Product add the next preceding Remainder;... | |
 | William Kinne - 1831 - 248 str.
...remainder may be found by the following rule. RULE.—Multiply the last remainder by the last divisor but one, and to the product add the preceding remainder;...multiply this sum by the next preceding divisor, and to this product add the next preceding remainder, and so on until all the remainders and divisors are... | |
 | Nicolas Pike - 1832 - 540 str.
...commonly made use of, when the divisor is a composite number, is RULE II. Multiply the lost remainder by the preceding divisor, or last but one, and to...preceding remainder ; and so on, till you have gone through all the divisors and remainders, to the tirst. EXAMPLE. 6)35397 divided by 150 1 the last remainder.... | |
 | Nicolas Pike - 1832 - 544 str.
...commonly made line of, when the divisor is a coinjwtiitf number, is Rvr.E II. Multiply the last remainder by the preceding divisor, or last but one, and to...the next preceding remainder ; and so on, till you bate gone through all the divisors and remainders, to the first. 0)35397 divided by 150 5)14233—5... | |
 | George Alfred - 1834 - 336 str.
...preceding divisor, or the last but one ; and to the product add the preceding remainder ; multiply the sum by the next preceding divisor, and to the product...preceding remainder, and so on, till you have gone through all the divisors and remainders, to the first ; the result will be the true remainder required.... | |
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Or multiply the last remainder by the preceding divisor, or last but one, and to the product add the preceding remainder; multiply this sum by the next preceding divisor, and to the product add the next preceding remainder ; and so on till you have gone... 
