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" From half the sum of the three sides subtract each side severally. Multiply... "
The artillerist's manual, and compendium of infantry exercise - Strana 294
autor/autoři: Frederick Augustus Griffiths - 1839
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1806 - 342 str.
...at per Acre ? Case 2. When the three Sides of a Triangle are given, to find the Area. RULE. 3. From Half the Sum of the three Sides subtract each Side...severally ; multiply the Half Sum and the three Remainders continually together, and the Square Root of the last Produdl will be the Area of the Triangle, that...
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The principles of architecture, Svazek 1

Peter Nicholson - 1809 - 426 str.
...f. i ii PROBLEM III. To find the area of a triangle, whose three sides only are given. From the half sum of the three sides, subtract each side severally;...square root of the product will be the area required. EXAMPLE I. Rcquireth the area of a triangle ABC, whose three sides AB, BC, and CA, are respectively...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - 1814 - 398 str.
...Ans. 6A. 3R. 18P. PROBLE To find the area of a triangle, when the three sides are. given. % RULE; From half the sum of the three sides subtract each side...severally ; multiply the half sum and the three remainders contiuually together, and the square root of the last product will be the area.* * DEMONSTRATION. Let...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1815 - 340 str.
...per acre ? Case 2. When the three sides of a triangle are given, to find the area. i RULE. 3. From half the sum of the three sides subtract each side severally ; multiply the half cum and the three remainders continually together, and the square root of the Iast product will be...
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The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817 - 306 str.
...three sides together, and take half that sum ; subtract each side separately from the half sum, then multiply the half sum and the three remainders together, and the square root of the last product will give the area I. Example. * Demonstration. The truth of this rule is obvious, because...
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A Treatise on Practical Mensuration in Eight Parts ...

Anthony Nesbit - 1824 - 476 str.
...\d. , PROBLEM V. To find the area of a triangle, the three sides only of which are given. RULE. From half the sum of the three sides subtract each side...severally ; multiply the half sum and the three remainders continually together; and the square root of the last product will be the area of the triangle. Jvofe...
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A Popular Course of Pure and Mixed Mathematics ...: With Tables of ...

Peter Nicholson - 1825 - 1046 str.
...52 Ofi2.5 Prob. 3. To find the area of a triangle, whose three sides only are given. From the half sum of the three sides, subtract each side severally...square root of the product will be the area required. Едг. Requireth the area of a triangle ABC, whose three »ides AB BC, and CA, are respectively 13,...
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A Treatise on the New Method of Land Surveying, with the Improved Plan of ...

Thomas Hornby (land surveyor.) - 1827 - 318 str.
...each side from that half sum ; then multiply the said half sum and the three remainders continually together ; and the square root of the product will be the area of the triangle. EXAMPLES. 1. — Required the area of the triangular field ABC, whose base AB is 650,...
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An Introduction to Mensuration and Practical Geometry

John Bonnycastle - 1829 - 256 str.
...— c2) X (c2— a— 56 MENSURATION 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. EXAMPLES. 1. Required the area of the triangle ABC, whose three sides BC, CA, and AB are 24, 36, and...
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A London Encyclopaedia, Or Universal Dictionary of Science, Art ..., Svazek 14

Thomas Curtis - 1829 - 810 str.
...sides, subtract each side separately, and multiply the half sum and the three remainders continually together; and the square root of the product will be the area. the sides Then by hence AD r: — E 1C, geAC, and AB, t» — «' "~~ 2 с ¿> — ; o AD —DB = —...
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